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Experiment 8 — Tunneling by Frustrated Total Internal Reflection

Objectives

By the end of this experiment you should be able to:

Textbook connection

Read §8.4–8.7, on the rectangular barrier and tunneling. The correspondence exploited here is the same form of differential equation within the barrier: for one polarization component in the air gap and the stationary quantum wavefunction in a rectangular barrier, both equations have the form

d2ψdz2=κ2ψ,\frac{d^2\psi}{dz^2} = \kappa^2\psi ,

with a real κ\kappa and hence exponentially decaying — not oscillating — solutions. Boundary conditions and transmitted quantities must still be handled separately in the two systems.

Theory

The evanescent wave

Light inside glass of index nn striking a glass–air interface at an angle θ\theta greater than the critical angle θc=arcsin⁡(1/n)\theta_c = \arcsin(1/n) is totally internally reflected. But the field does not stop at the interface: it continues into the air as an evanescent wave whose amplitude decays as e−κze^{-\kappa z} with

κ=2πλn2sin⁡2θ−1.\kappa = \frac{2\pi}{\lambda}\sqrt{n^2\sin^2\theta - 1} .

For n=1.52n = 1.52 at θ=45°\theta = 45° and λ=650 nm\lambda = 650\ \text{nm}, 1/κ1/\kappa is about 263 nm263\ \text{nm}, while the corresponding intensity decay length is about 131 nm131\ \text{nm}. The evanescent amplitude is small, but never exactly zero at a finite distance.

Frustrating it

Bring a second piece of glass close to the first. If the gap dd is comparable to 1/κ1/\kappa, the evanescent field still has appreciable amplitude when it reaches the second surface, where it can couple back into a propagating wave. Light appears on the far side of a gap that ray optics alone cannot describe. In the thick-gap tail, after correcting for incident illumination and camera dark signal, transmitted intensity has the form

I(d)=I0 e−2κd+Istray,I(d) = I_0\, e^{-2\kappa d} + I_{\text{stray}} ,

the factor of 2 appearing because intensity is proportional to squared field amplitude. I0I_0 here is an extrapolated tail amplitude, not the measured zero-gap intensity. The exact glass–air–glass transmission saturates toward unity as d→0d\to0 for matched, uncoated glass; it is not a single exponential over the whole contact image. Fresnel coupling depends on polarization and angle. Fit a region where the measured log-intensity is approximately linear in dd, and report its range.

The quantum barrier

A particle of energy EE incident on a rectangular barrier of height V0>EV_0 > E and width LL has a wavefunction that is a combination of growing and decaying exponentials inside the finite barrier. Their scale is set by

κq=2m(V0−E)ℏ,\kappa_q = \frac{\sqrt{2m(V_0 - E)}}{\hbar} ,

and the exact transmission coefficient for equal potentials on either side is

Texact=[1+V02sinh⁡2(κqL)4E(V0−E)]−1.T_{\rm exact}=\left[1+\frac{V_0^2\sinh^2(\kappa_q L)} {4E(V_0-E)}\right]^{-1} .

For κqL≫1\kappa_q L \gg 1, this approaches

T≈16E(V0−E)V02 e−2κqL.T \approx \frac{16E(V_0 - E)}{V_0^2}\, e^{-2\kappa_q L} .

Compare (8.2) with (8.4) and the large-width dependence in (8.3) with (8.6). Gap and barrier width play corresponding roles, but their decay constants have different physical inputs and the interface factors differ.

A potential barrier taller than particle energy, with a schematic oscillatory incident region, a nonoscillatory evanescent region, and a smaller transmitted oscillation.

Figure 8.1:The quantum side of the correspondence. The drawing is schematic; a finite barrier’s exact interior solution contains both exponential terms and must match the waves at both interfaces.

The Newton’s-rings trick

Controlling a sub-micrometre gap mechanically is difficult. Instead, use geometry: press a plano-convex lens of radius of curvature RR against the prism face. The gap between them at radial distance rr from the contact point is

d(r)=r22R,d(r) = \frac{r^{2}}{2R} ,

so a single image of the contact region contains a continuous, calculable range of gaps. For R=1000 mmR = 1000\ \text{mm}, d=500 nmd = 500\ \text{nm} at r=1.0 mmr = 1.0\ \text{mm} — a comfortable field of view for a USB microscope.

A photograph can sample many gap widths without moving the lens, provided the incident beam illuminates that region uniformly or a spatial reference image corrects it. With a separate, near-normal reflected-light view, Newton’s rings can calibrate RR; the ring relation assumes an approximately spherical surface, an air film, and one reflection phase reversal. Do not use the oblique total-internal-reflection image as a Newton’s-rings calibration.

Pre-lab

Apparatus

An expanded beam enters one short face of a right-angle prism, strikes its horizontal hypotenuse at an angle above critical, and exits the other short face after reflection; a lens above the hypotenuse receives light coupled through the thin air gap.

Figure 8.2:Frustrated total internal reflection. The lens approaches the prism’s hypotenuse from above. The curved air gap d(r)d(r) permits transmission near contact and reduces the reflected intensity there. The drawing shows the ports, not the camera’s imaging optics or a scale drawing of the gap.

Procedure

Setup and controls

Part A — Establishing total internal reflection

  1. Send the expanded beam through one short prism face so that it strikes the hypotenuse at 45°45° inside the glass. Verify the angle and measure or obtain the prism’s index at the laser wavelength. With the lens far away, confirm a bright reflected port and only stray light at the transmitted port.

  2. Measure the residual transmitted intensity with nothing in contact. This is IstrayI_{\text{stray}} and it sets the floor of your dynamic range. Reduce it — baffles and beam blocks — because the decay range is limited by the floor.

[ ] Checkpoint 1. Show the instructor the reflected and transmitted powers, and your measured stray floor relative to the brightest unsaturated transmitted signal you expect to measure. Estimate the available decay range before proceeding.

Part B — Newton’s rings, for the geometry

  1. Bring the lens gently to the planned clamp pressure. With a separate near-normal reflected-light view, illuminate the prism–air–lens contact and photograph Newton’s rings. Keep this view distinct from the 45°45° FTIR beam and block unwanted reflections.

  2. Measure dark-ring radii rmr_m about their common center. For the usual one-phase-reversal air film, adjacent dark rings satisfy rm+12−rm2=λRr_{m+1}^2-r_m^2=\lambda R. Fit squared radius against consecutive ring number to obtain RR from the slope, without assuming the central ring is order zero. Use the measured RR with its uncertainty; distorted rings invalidate the spherical-gap model.

Part C — The transmission curve

  1. Without changing the calibrated pressure, switch to the FTIR transmitted port. Recheck the contact center and ring shape. Do not assume the central gap is exactly zero merely because the pieces appear to touch.

  2. Image light transmitted through the lens at its exit port. Look for a bright contact region fading outward. Its apparent size depends on κ\kappa, curvature, beam profile, and the camera’s response.

  3. Take a series of exposures spanning the dynamic range: short exposures for the bright center, long ones for the tail, with the exposure times recorded so that you can splice them onto a common scale. Take a dark frame for each exposure time.

  4. Repeat at the same pressure to assess repeatability. Optionally repeat at another approved pressure, recalibrating the rings; deformation can create a flat center that must be excluded from the parabolic-gap fit.

Part D — The numerical companion

  1. Evaluate the rectangular-barrier formula numerically (see Analysis). Compare its thick-barrier slope with (8.6) and the optical tail slope after scaling each width by its own decay constant.

Analysis

From image to transmission curve

Convert pixel radius to physical radius with a scale imaged at the same magnification. Subtract a matched camera dark image, measure the stray floor separately, and correct or bound any illumination gradient; otherwise a beam profile can masquerade as gap decay. Radially average only if rings and illumination are approximately circular after image distortion correction. Convert rr to dd with (8.7), excluding a flattened center, saturated pixels, and the floor-dominated outer region. A constant unknown gap offset changes the fitted amplitude but not the tail slope.

import numpy as np
from scipy.optimize import curve_fit

d = r**2 / (2 * R)                           # meters; R is measured curvature
sel = (d >= d_tail_min) & (d <= d_tail_max)  # inspect this range first
# I and sI are dark-subtracted transmission and its absolute uncertainty.
# floor comes from independent no-contact measurements at this detector.
model = lambda d, A, kappa: A * np.exp(-2 * kappa * d) + floor
popt, pcov = curve_fit(model, d[sel], I[sel],
                       p0=[I[sel].max(), 4e6], sigma=sI[sel],
                       absolute_sigma=True, bounds=(0, np.inf))
kappa, skappa_stat = popt[1], np.sqrt(pcov[1, 1])
print(f"kappa = {kappa:.3g} +/- {skappa_stat:.2g} 1/m (fit only)")
print(f"decay length 1/(2 kappa) = {1/(2*kappa)*1e9:.0f} nm")

The printed uncertainty is conditional on the chosen fit region, RR, floor, and illumination correction. Repeat with plausible RR and floor values and adjacent tail windows; report those sensitivities separately. Compare κ\kappa with (8.2), propagating uncertainty in nn, θ\theta, and λ\lambda. Near the critical angle κ\kappa is angle-sensitive: evaluate dκ/dθd\kappa/d\theta and state how well you would need to know θ\theta for a 5% measurement of κ\kappa.

The numerical rectangular-barrier comparison

Evaluate the exact matched-asymptote formula (8.5). The code also handles E=V0E=V_0 by its continuous limit:

import numpy as np

hbar = 1.054571817e-34
me   = 9.1093837015e-31
eV   = 1.602176634e-19

def transmission(E_eV, V0_eV, L_nm):
    E, V0, L = E_eV*eV, V0_eV*eV, L_nm*1e-9
    if E <= 0 or V0 <= 0 or L < 0:
        raise ValueError("Require E,V0 > 0 and L >= 0")
    if E < V0:
        kap = np.sqrt(2*me*(V0 - E)) / hbar
        return 1.0 / (1 + (V0**2 * np.sinh(kap*L)**2) / (4*E*(V0 - E)))
    if np.isclose(E, V0, rtol=0, atol=1e-12*eV):
        return 1.0 / (1 + me*V0*L**2/(2*hbar**2))
    kk = np.sqrt(2*me*(E - V0)) / hbar
    return 1.0 / (1 + (V0**2 * np.sin(kk*L)**2) / (4*E*(E - V0)))

Plot TT against LL for E<V0E < V_0 on a logarithmic axis. Its slope approaches −2κq-2\kappa_q only for a thick barrier. Then plot TT against EE through and above V0V_0. Above-barrier transmission maxima arise from wave interference at the two interfaces; optical slabs have an analogous effect.

Plot the measured optical tail and quantum thick-barrier curve using κd\kappa d and κqL\kappa_q L on the horizontal axis. Compare their slopes after allowing separate vertical offsets. Do not expect the complete curves to coincide: boundary matching, polarization, and contact geometry differ.

Post-lab questions

Going further