A5. Conversion of Units to SI January 1, 2025
Appendix A5 317
A5 Conversion of Units to SI ¶ The following relationships can be used to convert customary physical units into SI units. The conversion factors here are rounded to seven significant digits.
l ( m ) = 39.37008 l ( i n ) ( A 5 / 1 ) l(m) = 39.370 08 l(in) (A5/1) l ( m ) = 39.37008 l ( in ) ( A 5/1 ) l ( i n ) = 2.54 × 1 0 − 2 l ( m ) ( A 5 / 2 ) l(in) = 2.54 \times 10^{-2}l(m) (A5/2) l ( in ) = 2.54 × 1 0 − 2 l ( m ) ( A 5/2 ) l ( m ) = 3.28084 l ( f t ) ( A 5 / 3 ) l(m) = 3.280 84 l(ft) (A5/3) l ( m ) = 3.28084 l ( f t ) ( A 5/3 ) l ( f t ) = 0.3048 l ( m ) ( A 5 / 4 ) l(ft) = 0.3048 l(m) (A5/4) l ( f t ) = 0.3048 l ( m ) ( A 5/4 ) l ( m ) = 6.213712 × 1 0 − 4 l ( m i ) ( A 5 / 5 ) l(m) = 6.213 712 \times 10^{-4}l(mi) (A5/5) l ( m ) = 6.213712 × 1 0 − 4 l ( mi ) ( A 5/5 ) l ( m i ) = 1.609344 × 1 0 3 l ( m ) ( A 5 / 6 ) l(mi) = 1.609 344 \times 10^{3}l(m) (A5/6) l ( mi ) = 1.609344 × 1 0 3 l ( m ) ( A 5/6 ) C ( m s − 1 ) = 0.44704 C ( m p h ) ( A 5 / 7 ) C(m s^{-1}) = 0.447 04 C(mph) (A5/7) C ( m s − 1 ) = 0.44704 C ( m p h ) ( A 5/7 ) C ( k m / h ) = 1.609344 C ( m p h ) ( A 5 / 8 ) C(km/h) = 1.609 344 C(mph) (A5/8) C ( km / h ) = 1.609344 C ( m p h ) ( A 5/8 ) C ( m p h ) = 0.621371 C ( k m / h ) ( A 5 / 9 ) C(mph) = 0.621 371 C(km/h) (A5/9) C ( m p h ) = 0.621371 C ( km / h ) ( A 5/9 ) C ( m p h ) = 2.236936 C ( m s − 1 ) ( A 5 / 10 ) C(mph) = 2.236 936 C(m s^{-1}) (A5/10) C ( m p h ) = 2.236936 C ( m s − 1 ) ( A 5/10 ) V ( U S g a l ) = 2.641721 × 1 0 2 V ( m 3 ) ( A 5 / 11 ) V(US gal) = 2.641 721 \times 10^{2}V(m^{3}) (A5/11) V ( U S g a l ) = 2.641721 × 1 0 2 V ( m 3 ) ( A 5/11 ) V ( m 3 ) = 3.785412 × 1 0 − 3 V ( U S g a l ) ( A 5 / 12 ) V(m^{3}) = 3.785 412 \times 10^{-3}V(US gal) (A5/12) V ( m 3 ) = 3.785412 × 1 0 − 3 V ( U S g a l ) ( A 5/12 ) V ( i m p g a l ) = 2.199692 × 1 0 2 V ( m 3 ) ( A 5 / 13 ) V(imp gal) = 2.199 692 \times 10^{2}V(m^{3}) (A5/13) V ( im p g a l ) = 2.199692 × 1 0 2 V ( m 3 ) ( A 5/13 ) V ( m 3 ) = 4.54609 × 1 0 − 3 V ( i m p g a l ) ( A 5 / 14 ) V(m^{3}) = 4.546 09 \times 10^{-3}V(imp gal) (A5/14) V ( m 3 ) = 4.54609 × 1 0 − 3 V ( im p g a l ) ( A 5/14 ) m ( t ) = 1 0 − 3 m ( k g ) ( A 5 / 15 ) m(t) = 10^{-3}m(kg) (A5/15) m ( t ) = 1 0 − 3 m ( k g ) ( A 5/15 ) m ( k g ) = 1 0 3 m ( t ) ( A 5 / 16 ) m(kg) = 10^{3}m(t) (A5/16) m ( k g ) = 1 0 3 m ( t ) ( A 5/16 ) m ( l b ) = 2.204623 m ( k g ) ( A 5 / 17 ) m(lb) = 2.204 623 m(kg) (A5/17) m ( l b ) = 2.204623 m ( k g ) ( A 5/17 ) m ( k g ) = 0.45359237 m ( l b ) ( A 5 / 18 ) m(kg) = 0.453 592 37 m(lb) (A5/18) m ( k g ) = 0.45359237 m ( l b ) ( A 5/18 ) 318 Appendix A5
F ( l b f ) = 0.2248089 F ( N ) ( A 5 / 19 ) F(lbf) = 0.224 808 9 F(N) (A5/19) F ( l b f ) = 0.2248089 F ( N ) ( A 5/19 ) F ( N ) = 4.448222 F ( l b f ) ( A 5 / 20 ) F(N) = 4.448 222 F(lbf) (A5/20) F ( N ) = 4.448222 F ( l b f ) ( A 5/20 ) p ( i n H g ) = 2.067099 × 1 0 − 6 p ( P a ) ( A 5 / 21 ) p(inHg) = 2.067 099 \times 10^{-6}p(Pa) (A5/21) p ( in H g ) = 2.067099 × 1 0 − 6 p ( P a ) ( A 5/21 ) p ( P a ) = 3.386389 × 1 0 3 p ( i n H g ) ( A 5 / 22 ) p(Pa) = 3.386 389 \times 10^{3}p(inHg) (A5/22) p ( P a ) = 3.386389 × 1 0 3 p ( in H g ) ( A 5/22 ) p ( b a r ) = 1 0 − 5 p ( P a ) ( A 5 / 23 ) p(bar) = 10^{-5}p(Pa) (A5/23) p ( ba r ) = 1 0 − 5 p ( P a ) ( A 5/23 ) p ( P a ) = 1 0 5 p ( b a r ) ( A 5 / 24 ) p(Pa) = 10^{5}p(bar) (A5/24) p ( P a ) = 1 0 5 p ( ba r ) ( A 5/24 ) p ( p s i ) = 1.450377 × 1 0 − 4 p ( P a ) ( A 5 / 25 ) p(psi) = 1.450 377 \times 10^{-4}p(Pa) (A5/25) p ( p s i ) = 1.450377 × 1 0 − 4 p ( P a ) ( A 5/25 ) p ( p s i ) = 14.50377 p ( b a r ) ( A 5 / 26 ) p(psi) = 14.503 77 p(bar) (A5/26) p ( p s i ) = 14.50377 p ( ba r ) ( A 5/26 ) p ( P a ) = 6.894757 × 1 0 3 p ( p s i ) ( A 5 / 27 ) p(Pa) = 6.894 757 \times 10^{3}p(psi) (A5/27) p ( P a ) = 6.894757 × 1 0 3 p ( p s i ) ( A 5/27 ) p ( b a r ) = 6.894757 × 1 0 − 2 p ( p s i ) ( A 5 / 28 ) p(bar) = 6.894 757 \times 10^{-2}p(psi) (A5/28) p ( ba r ) = 6.894757 × 1 0 − 2 p ( p s i ) ( A 5/28 ) p ( k g f / c m 2 ) = 1.019716 × 1 0 − 5 p ( P a ) ( A 5 / 29 ) p(kg_{f}/cm^{2}) = 1.019 716 \times 10^{-5}p(Pa) (A5/29) p ( k g f / c m 2 ) = 1.019716 × 1 0 − 5 p ( P a ) ( A 5/29 ) p ( k g f / c m 2 ) = 1.019716 p ( b a r ) ( A 5 / 30 ) p(kg_{f}/cm^{2}) = 1.019 716 p(bar) (A5/30) p ( k g f / c m 2 ) = 1.019716 p ( ba r ) ( A 5/30 ) p ( P a ) = 9.80665 × 1 0 4 p ( k g f / c m 2 ) ( A 5 / 31 ) p(Pa) = 9.806 65 \times 10^{4}p(kg_{f}/cm^{2}) (A5/31) p ( P a ) = 9.80665 × 1 0 4 p ( k g f / c m 2 ) ( A 5/31 ) p ( b a r ) = 0.980665 p ( k g f / c m 2 ) ( A 5 / 32 ) p(bar) = 0.980 665 p(kg_{f}/cm^{2}) (A5/32) p ( ba r ) = 0.980665 p ( k g f / c m 2 ) ( A 5/32 ) T ( ∘ F ) = 1.8 × [ T ( K ) − 273.15 ] + 32 ( A 5 / 33 ) T(^{\circ} F) = 1.8 \times [T(K) - 273.15] + 32 (A5/33) T ( ∘ F ) = 1.8 × [ T ( K ) − 273.15 ] + 32 ( A 5/33 ) T ( K ) = T ( ∘ F ) − 32 1.8 + 273.15 ( A 5 / 34 ) T(K) = \frac{T(^{\circ} F) - 32}{1.8} + 273.15 (\mathrm{A}5/34) T ( K ) = 1.8 T ( ∘ F ) − 32 + 273.15 ( A 5/34 ) W ( h p i m p ) = 1.341022 × 1 0 − 3 W ˙ ( W ) ( A 5 / 35 ) W(hp imp) = 1.341 022 \times 10^{-3}\dot{W}(W) (A5/35) W ( h p im p ) = 1.341022 × 1 0 − 3 W ˙ ( W ) ( A 5/35 ) W ( W ) = 7.456999 × 1 0 2 W ˙ ( h p i m p ) ( A 5 / 36 ) W(W) = 7.456 999 \times 10^{2}\dot{W}(hp imp) (A5/36) W ( W ) = 7.456999 × 1 0 2 W ˙ ( h p im p ) ( A 5/36 ) W ( h p ) = 1.359622 × 1 0 − 3 W ˙ ( W ) ( A 5 / 37 ) W(hp) = 1.359 622 \times 10^{-3}\dot{W}(W) (A5/37) W ( h p ) = 1.359622 × 1 0 − 3 W ˙ ( W ) ( A 5/37 ) W ( W ) = 7.354988 × 1 0 2 W ˙ ( h p ) ( A 5 / 38 ) W(W) = 7.354 988 \times 10^{2}\dot{W}(hp) (A5/38) W ( W ) = 7.354988 × 1 0 2 W ˙ ( h p ) ( A 5/38 )