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Screenshot of the Geometric Optics simulation

Figure 1:Place a lens or mirror, drag the object, and watch real and virtual images form. This is the interactive companion to the Gaussian imaging constructions later in the chapter.

Interactive simulation: Geometric Optics

1Introduction

Geometrical optics is an old subject, but it is still essential to understand and design optical instruments such as cameras, microscopes, telescopes etc. Geometrical optics started long before light was described as a wave as is done in wave optics, and long before it was discovered that light is an electromagnetic wave and that optics is part of electromagnetism.

In this chapter, we go back in history and treat geometrical optics. That may seem strange now that we have a much more accurate and better theory at our disposal. However, the predictions of geometrical optics are under quite common circumstances very useful and also very accurate. In fact, for many optical systems and practical instruments there is no alternative to geometrical optics because more accurate theories are much too complicated to use.

When a material is illuminated, its molecules start to radiate spherical waves (more precisely, they radiate like tiny electric dipoles) and the total wave scattered by the material is the sum of all these spherical waves. A time-harmonic wave has at every point in space and at every instant of time a well defined phase. A wavefront is a surface of equal phase at a fixed time. In an isotropic medium it moves along its local normal at the phase velocity.

For a plane wave in an isotropic medium, constant-phase surfaces are planes; their normal is the direction of the wave vector and energy flow. A curved wavefront behaves locally like a plane wave when its radius of curvature and the optical features are large compared with the wavelength. Geometrical optics then describes its propagation by rays.

Geometrical optics is based on the intuitive idea that light consists of a bundle of rays. But what is a ray?

Consider a point source at some distance before an opaque screen with an aperture. According to the ray picture, the light distribution on a second screen further away from the source and parallel to the first screen is simply an enlarged copy of the aperture (see Figure 2). The copy is enlarged due to the fanning out of the rays. However, this description is only accurate when the wavelength of the light is very small compared to the diameter of the aperture. If the aperture is only ten times the wavelength, the pattern is much broader due to the bending of the rays around the edge of the aperture. This phenomenon is called diffraction. Diffraction cannot be explained by geometrical optics and will be studied in Scalar Diffraction Optics.

Two side-by-side screens: a wide rectangular aperture casts a sharp enlarged patch; a narrow aperture spreads light beyond the geometric patch.

Figure 2:Light distribution on a screen due to a rectangular aperture. Left: for a large aperture, we get an enlarged copy of the aperture. Right: for an aperture that is of the order of the wavelength there is strong bending (diffraction) of the light.

Geometrical optics is accurate when the sizes of the objects in the system are large compared to the wavelength. It is possible to derive geometrical optics from Maxwell’s equations by formally expanding the electromagnetic field in a power series in the wavelength and retaining only the first term of this expansion[1]. However, this derivation is not rigorous because the power series generally does not converge (it is a so-called asymptotic series).

Although it is possible to incorporate polarization into geometrical optics, this is not standard theory and we will not consider polarization effects in this chapter.

2Principle of Fermat

The starting point of the treatment of geometrical optics is the

The phase velocity in a material of refractive index nn is c/nc/n, where c≈3×108c\approx3\times10^8 m/s is the vacuum speed. The optical path integral below measures the phase delay at one frequency. In a nondispersive medium this delay equals the ray’s travel time; a pulse in a dispersive medium generally propagates at a different group velocity. Rømer’s 1676 observations of Io’s eclipses established a finite light-travel time.

Let r(s)\mathbf{r}(s) be a ray with ss the length parameter. The ray links two points SS and PP. Suppose that the refractive index varies with position: n(r)n(\mathbf{r}). Over the infinitesimal distance from ss to s+dss+\mathrm{d}s, the speed of the light is

cn(r(s)).\begin{align*} \frac{c}{n(\mathbf{r}(s))}. \end{align*}

The corresponding differential phase delay, expressed in seconds, is:

dt=n(r(s))cds,\begin{align*} \mathrm{d}t = \frac{n(\mathbf{r}(s))}{c} \mathrm{d}s, \end{align*}

The integrated phase delay from SS to PP is:

tS→P=∫0sPn(r(s))cds,\begin{align*} t_{S \rightarrow P} = \int_0^{s_P} \frac{n(\mathbf{r}(s))}{c} \mathrm{d}s, \end{align*}

where sPs_P is the distance along the ray from S to P. The optical path length [m] of the ray between S and P is defined by:

OPL=∫0sPn(r(s))ds,\begin{align*} \text{OPL} = \int_0^{s_P} n(\mathbf{r}(s)) \mathrm{d}s, \end{align*}

So the OPL is the distance weighted by the refractive index.

Historical drawing of rays curving near hot ground from a palm tree toward an observer; backward extensions place an inverted virtual tree below the ground.

Figure 3:Because the temperature close to the ground is higher, the refractive index is lower there. Therefore the rays bend upwards, creating a mirror image of the tree below the ground. (From Popular Science Monthly Volume 5, Public Domain, link).

Remark. More than one stationary path can connect two points. For example, a direct ray and a reflected ray can have different travel times. The reflection calculation below minimizes travel time among paths constrained to touch the mirror; it does not compare that path with the direct ray.

3Some Consequences of Fermat’s Principle

In homogeneous matter, the refractive index is constant and therefore paths of shortest OPL are straight lines. Hence in homogeneous matter rays are straight lines.

When the refractive index is a function of position, as in air with a temperature gradient, the rays bend towards regions of higher refractive index. In the case of Figure 3 for example, on a warm day, the ray from the top of the tree to the eye of the observer passes close to the ground because there the temperature is higher and hence the refractive index is smaller. Although the curved path is longer than the straight path, the total travel time of the light is less because near the ground the light speed is higher (since the refractive index is smaller). The observer gets the impression that the tree is upside down under the ground.

Consider the mirror shown in Figure 4. In the homogeneous medium above it, a direct ray and a ray reflected by the mirror can connect PP and QQ. We now minimize travel time over the paths that touch the mirror. Let the xx-axis be the intersection of the mirror and the plane through the points PP and QQ and perpendicular to the mirror. Let the yy-axis be normal to the mirror. Let (xP,yP)(x_P, y_P) and (xQ,yQ)(x_Q,y_Q) be the coordinates of PP and QQ, respectively. If (x,0)(x,0) is the point where a ray from PP to QQ hits the mirror, the travel time of that ray is

ncd1(x)+ncd2(x)=nc(x−xP)2+yP2+nc(xQ−x)2+yQ2,\begin{align*} \frac{n}{c}d_1(x) + \frac{n}{c}d_2(x) = \frac{n}{c}\sqrt{ (x-x_P)^2 + y_P^2} +\frac{n}{c} \sqrt{ (x_Q-x)^2 + y_Q^2}, \end{align*}

where nn is the refractive index in y>0y>0. Among paths constrained to reflect at the mirror, the stationary point (x,0)(x,0) satisfies

ddx[d1(x)+d2(x)]=(x−xP)d1(x)−(xQ−x)d2(x)=0.\begin{align*} \frac{d }{d x} [d_1(x) + d_2(x)] = \frac{(x-x_P)}{d_1(x)} - \frac{(x_Q-x)}{d_2(x)} =0. \end{align*}

Hence

sin⁡θi=sin⁡θr,\begin{align*} \sin \theta_i = \sin \theta_r, \end{align*}

or

θr=θi.\begin{align*} \theta_r = \theta_i. \end{align*}

where θi\theta_i and θr\theta_r are the angles of incidence and reflection as shown in Figure 4.

A ray from P reflects at point x on a horizontal mirror and reaches Q; incidence and reflection angles are measured from the vertical normal.

Figure 4:Ray from PP to QQ via the mirror.

Next, we consider refraction at an interface. Let y=0y=0 be the interface between a medium with refractive index nin_i in y>0y>0 and a medium with refractive index ntn_t in y<0y<0. We use the same coordinate system as in the case of reflection above. Let (xP,yP)(x_P,y_P) and (xQ,yQ)(x_Q,y_Q) with yP>0y_P>0 and yQ<0y_Q<0 be the coordinates of two points PP and QQ as shown in Figure 5. What path will a ray follow that goes from PP to QQ? Since the refractive index is constant in both half spaces, the ray is a straight line in both media. Let (x,0)(x,0) be the coordinate of the intersection point of the ray with the interface. Then the travel time is

nicd1(x)+ntcd2(x)=nic(x−xP)2+yP2+ntc(xQ−x)2+yQ2.\begin{align*} \frac{n_i}{c} d_1(x) + \frac{n_t}{c} d_2(x) = \frac{n_i}{c} \sqrt{(x-x_P)^2 + y_P^2} + \frac{n_t}{c} \sqrt{(x_Q-x)^2 + y_Q^2}. \end{align*}

The OPL is stationary with respect to the crossing point, so

ddx[nid1(x)+ntd2(x)]=ni(x−xP)d1(x)−nt(xQ−x)d2(x)=0.\begin{align*} \frac{d}{d x} \left[ n_i d_1(x) + n_t d_2(x)\right] = n_i \frac{(x-x_P)}{d_1(x)} - n_t \frac{(x_Q-x)}{d_2(x)}=0. \end{align*}

where the phase delay has been multiplied by the vacuum light speed. Eq. (10) implies

nisin⁡θi=ntsin⁡θt,\begin{align*} n_i \sin \theta_i = n_t \sin \theta_t, \end{align*}

where θi\theta_i and θt\theta_t are the angles between the ray and the normal to the surface in the upper half space and the lower half space, respectively (Figure 5).

A ray from P crosses a horizontal boundary at x and reaches Q in the lower medium; incidence and transmission angles are measured from the normal.

Figure 5:Ray from PP to QQ refracted by an interface.

Screenshot of the Bending Light simulation

Figure 6:Refraction and reflection at a planar interface with adjustable indices. Measure θi\theta_i and θt\theta_t and check that nisin⁡θi=ntsin⁡θtn_i\sin\theta_i = n_t\sin\theta_t matches the protractor — the same Snell’s law just derived from Fermat’s principle.

Interactive simulation: Bending Light

Thus Fermat’s principle gives the reflection and refraction laws. Matching the phase of electromagnetic fields along an interface gives an independent derivation of Snell’s law.

4Perfect Imaging by Conic Sections

In this section, the conic sections ellipse, hyperbola and parabola are important. In Figure 8 their definitions are shown as a quick reminder[3].

Parabola uses equal focus and directrix distances; ellipse uses a constant sum of distances to two foci; hyperbola uses a constant absolute difference.

Geometric construction of conic sections (ellipse, hyperbola, and parabola) showing their traditional definitions. The ellipse is the locus of points with constant sum of distances to two foci, the hyperbola has a constant difference of distances, and the parabola maintains equal distances to a focus and a directrix.

Focus F and horizontal directrix through D define curves through P: ellipse e equals 0.5, parabola e equals 1, and hyperbola e equals 2.

Figure 8:Conic sections through the focus–directrix relation ∣PF∣=e∣PD∣|PF|=e|PD|: e<1e<1 gives an ellipse, e=1e=1 a parabola, and e>1e>1 a hyperbola. The horizontal line through DD is the common directrix in this drawing.

We start by explaining what in geometrical optics is meant by perfect imaging. Let SS be a point source. The rays perpendicular to the spherical wave fronts emitted by SS radially fan out from SS. Due to objects such as lenses etc. the spherical wave fronts are deformed and the directions of the rays are made to deviate from the radial propagation direction. If every ray in a cone from SS meets again at PP, as in Figure 9, PP is a perfect geometrical image of SS. For an ideal stigmatic system, the wavefront arriving at PP also has equal optical phase across the contributing aperture. Fermat’s stationarity condition alone does not say that arbitrary rays have equal travel times. By reversing the direction of the rays, SS is similarly a perfect image of PP. The optical system in which this happens is called stigmatic for the two points SS and PP.

Diverging rays and circular wavefronts from S enter an optical system; the outgoing rays converge at image point P and diverge beyond it.

Figure 9:Perfect imaging: a cone of rays which diverge from SS and all intersect in point PP. The rays continue after PP.

Remark. The concept of a perfect image point exists only in geometrical optics. In reality, finite apertures of lenses and other imaging systems cause diffraction due to which image points are never perfect but blurred.

We summarize the main examples of stigmatic systems.

1. Perfect focusing and imaging by refraction. A parallel bundle of rays propagating in a medium with refractive index n2n_2 can be focused into a point FF in a medium with refractive index n1n_1. If n2>n1n_2>n_1, the interface between the media should be a hyperbola with focus FF, whereas if n2<n1n_2<n_1 the interface should be an ellipse with focus FF. By reversing the rays we obtain perfect collimation. Therefore, a point SS in air can be perfectly imaged onto a point FF in air by inserting a piece of glass in between them with hyperbolic surfaces. These properties are derived in Problem 2.2.

2. Perfect focusing of parallel rays by a mirror. A bundle of parallel rays in air can be focused into a point FF by a mirror of parabolic shape with FF as focus. This is derived in Problem 2.3. By reversing the arrows, we get (within geometrical optics) a perfectly parallel beam. Parabolic mirrors are used everywhere, from automobile headlights to radio telescopes.

Remark.

Although we found that conic surfaces give perfect imaging for a certain pair of points, other points do not have perfect images in the sense that for a certain cone of rays, all rays are refracted (or reflected) to the same point.

5Gaussian Geometrical Optics

We have seen that, although by using lenses or mirrors which have surfaces that are conic sections we can perfectly image a certain pair of points, for other points the image is not perfect. The imperfections are caused by rays that make larger angles with the optical axis, i.e. with the symmetry axis of the system. Rays for which these angles are small are called paraxial rays. Because for paraxial rays the angles of incidence and transmission at the surfaces of the lenses are small, the sines of the angles in Snell’s Law are replaced by the angles themselves:

niθi=ntθt(paraxial rays only).\begin{align*} n_i \theta_i = n_t \theta_t \quad \text{(paraxial rays only)}. \end{align*}

This approximation greatly simplifies the calculations. At first paraxial order, a smooth rotationally symmetric surface can be replaced by a sphere with the same curvature at its vertex. Higher-order terms determine its aberrations outside that approximation. Spherical surfaces are not only simpler in the derivations but they are also much easier to manufacture. Hence in the optical industry spherical surfaces are used a lot. To reduce imaging errors caused by non-paraxial rays one applies two strategies: 1. adding more spherical surfaces; 2. replacing one of the spherical surfaces (typically the last before image space) by a non-sphere.

Screenshot of the Optics Lab simulation

Figure 10:An open optical bench: rays, parallel and divergent beams, lenses, mirrors, and refracting interfaces. Build the single-surface and thin-lens geometries of this section and watch where the rays meet.

Interactive simulation: Optics Lab

5.1Gaussian Imaging by a Single Spherical Surface

We will first show that within Gaussian optics a single spherical surface between two media with refractive indices n1<n2n_1< n_2 images all points perfectly (Figure 11). The sphere has radius RR and center CC which is inside medium 2. We consider a point object SS to the left of the surface. We draw a ray from SS perpendicular to the surface. The point of intersection is VV. Since for this ray the angle of incidence with the local normal on the surface vanishes, the ray continues into the second medium without refraction and passes through the center CC of the sphere. Next we draw a ray that hits the spherical surface at some point AA and draw the refracted ray in medium 2 using Snell’s law in the paraxial form Eq. (12). Note that the angles of incidence and transmission must be measured with respect to the local normal at AA, i.e. with respect to CACA. We assume that this ray intersects the first ray at point PP. We will show that within the approximation of Gaussian geometrical optics, all rays from SS pass through PP. Furthermore, with respect to a coordinate system (y,z)(y,z) with origin at VV, the zz-axis pointing from VV to CC and the yy-axis positive upwards as shown in Figure 11, we have:

−n1so+n2si=P,\begin{align*} -\frac{n_1}{s_o } + \frac{n_2}{s_i} = {\cal P}, \end{align*}

where

P=n2−n1R,{\cal P} = \frac{n_2-n_1}{R},

is called the power of the surface and where sos_o and sis_i are the zz-coordinates of SS and PP, respectively, hence s0<0s_0<0 and si>0s_i>0 in Figure 11.

Rays from object S cross a convex boundary from n1 into higher-index n2 and meet at P; vertex V, center C, focal point Fi, and ray angles are labeled.

Figure 11:Imaging by a spherical interface between two media with refractive indices n2>n1n_2>n_1.

Proof.

It suffices to show that PP is independent of the ray, i.e. of AA. We will do this by expressing sis_i in terms of sos_o and showing that the result is independent of AA. Let α1\alpha_1 and α2\alpha_2 be the angles of the rays SASA and APAP with the zz-axis as shown in Figure 11. Let θi\theta_i be the angle of incidence of ray SASA with the local normal CACA on the surface and θt\theta_t be the angle of refraction. By considering the angles in triangle ΔSCA\Delta \text{SCA} we find

θi=α1+φ.\begin{align*} \theta_i = \alpha_1 + \varphi. \end{align*}

Similarly, from Δ CPA\Delta \,\text{CPA} we find

θt=−α2+φ.\begin{align*} \theta_t=-\alpha_2 + \varphi. \end{align*}

By substitution into the paraxial version of Snell’s Law Eq. (12), we obtain

n1α1+n2α2=(n2−n1)φ.\begin{align*} n_1 \alpha_1 + n_2 \alpha_2 = (n_2-n_1) \varphi. \end{align*}

Let yAy_A and zAz_A be the coordinates of point AA. Since so<0s_o<0 and si>0s_i>0 we have

α1≈tan⁡(α1)=yAzA−so,        α2≈tan⁡(α2)=yAsi−zA.\begin{align*} \alpha_1 \approx \tan(\alpha_1) = \frac{y_A}{z_A-s_o}, \;\; \;\; \alpha_2\approx \tan(\alpha_2)= \frac{y_A}{s_i-z_A}. \end{align*}

Furthermore,

φ≈sin⁡φ≈yAR.\begin{align*} \varphi \approx \sin \varphi \approx \frac{y_A}{R}. \end{align*}

which is small for paraxial rays. Hence,

zA=R−Rcos⁡φ=R−R(1−φ22)=R2φ2≈0,\begin{align*} z_A=R-R\cos\varphi = R - R\left(1-\frac{\varphi^2}{2}\right)= \frac{R}{2}\varphi^2 \approx 0, \end{align*}

because it is second order in yAy_A and therefore is neglected in the paraxial approximation. Then, Eq. (18) becomes

α1=−yAso,α2=yAsi.\begin{align*} \alpha_1 = -\frac{y_A}{s_o}, \quad \alpha_2 =\frac{y_A}{s_i}. \end{align*}

By substituting Eq. (21) and Eq. (19) into Eq. (17) we find

−n1soyA+n2siyA=n2−n1RyA,\begin{align*} -\frac{n_1}{s_o} y_A + \frac{n_2}{s_i} y_A = \frac{n_2-n_1}{R} y_A, \end{align*}

or

−n1so+n2si=n2−n1R,\begin{align*} -\frac{n_1}{s_o } + \frac{n_2}{s_i} = \frac{n_2-n_1}{R}, \end{align*}

which is Eq. (13). It implies that sis_i, and hence PP, is independent of yAy_A, i.e. of the ray chosen. Therefore, PP is a perfect image within the approximation of Gaussian geometrical optics.

When so→−∞s_o \rightarrow -\infty, the incident rays are parallel to the zz-axis in medium 1 and the corresponding image point FiF_i is called the second focal point or image focal point. Its zz-coordinate is given by:

fi=n2P=n2Rn2−n1,\begin{align*} f_i = \frac{n_2}{{\cal P}}=\frac{n_2 R}{n_2-n_1}, \end{align*}

The absolute value of fif_i is called the second focal length or image focal length. For R>0R>0, the signed value fif_i is negative when n2<n1n_2<n_1. When si→∞s_i\rightarrow \infty, the rays after refraction are parallel to the zz-axis and we get so→−n1R/(n2−n1)s_o \rightarrow -n_1 R/(n_2-n_1). The object point for which the rays in medium 2 are parallel to the zz-axis is called the first focal point or object focal point FoF_o. Its zz-coordinate is:

fo=−n1P=−n1Rn2−n1.\begin{align*} f_o=-\frac{n_1}{{\cal P}}= -\frac{n_1 R}{n_2-n_1}. \end{align*}

The absolute value ∣fo∣|f_o| of fof_o is called the front focal length or object focal length.

With Eq. (24) and Eq. (25), Eq. (13) can be rewritten as:

−n1so+n2si=P=n2fi=−n1fo.\begin{align*} -\frac{n_1}{s_o} + \frac{n_2}{s_i} = {\cal P} =\frac{n_2}{f_i}= -\frac{n_1}{f_o}. \end{align*}

5.2Virtual Images and Virtual Objects of a Single Spherical Surface

If we adopt the sign convention listed in Table 1 below, it turns out that Eq. (13) holds generally. So far we have considered a convex surface of which the center CC is to the right of the surface, but Eq. (13) applies also to a concave surface of which the center is to the left of the surface, provided that the radius RR is chosen negative. The convention for the sign of the radius is illustrated in Figure 12.

Spherical boundary has negative signed radius when its center C is left of vertex V and positive radius when C is right.

Figure 12:Sign convention for the radius RR of a spherical surface

If the power P{\cal P} given by Eq. (14) is positive, then the surface makes bundles of incident rays convergent or less divergent. If the power is negative, incident bundles are made divergent or less convergent. The power of the surface can be negative for two reasons:

  1. RR>0 and n1>n2n_1>n_2, or

  2. RR<0 and n1<n2n_1<n_2, but the effect of the two cases is the same. For any object to the left of the surface: so<0s_o<0, Eq. (26) and a negative power imply that si<0s_i<0, which suggests that the image is to the left of the surface. Indeed, in both cases, the diverging ray bundle emitted by S is made more strongly divergent by the surface. By extending these rays in image space back to object space (without refraction at the surface), they are seen to intersect in a point PP to the left of the surface. This implies that for an observer at the right of the surface it looks as if the diverging rays in image space are emitted by PP. Because there is no actual concentration of light intensity at PP, it is called a virtual image, in contrast with the real images that occur to the right of the surface and where there is an actual concentration of light energy. We have in this case fo>0f_o>0 and fi<0f_i<0, which means that the object and image focal points are to the right and left, respectively, of the surface.

Note that also when the power is positive, a virtual image can occur, namely when the object SS is in between the object focal point FoF_o and the surface. Then the bundle of rays from S is so strongly diverging that the surface cannot convert it into a convergent bundle and hence again the rays in image space seem to come from a point PP to the left of the surface. This agrees with the fact that when P>0{\cal P}>0 and fo<so<0f_o< s_o<0, Eq. (26) implies that si<0s_i<0.

At a concave boundary from n1 into higher-index n2, a ray from S bends away from the axis and its backward extension meets a virtual image P left of the boundary.

Figure 13:Imaging by a concave surface (R<0R<0) with n2>n1n_2>n_1. All image points are to the left of the surface, i.e. are virtual (si<0s_i<0).

Finally we look at a case in which there is a bundle of convergent rays incident on the surface from the left. If extended into the right medium without refraction, these rays would intersect in a point SS. Since this point is not actually present, it is called a virtual object point, in contrast to real object points which are to the left of the surface. The coordinate of a virtual object point is positive: so>0s_o>0. One may wonder why we look at this case. The reason is that if we have several spherical surfaces behind each other, we can compute the image of an object point by first determining the intermediate image by the leftmost surface and then use this intermediate image as the object for the next surface and so on. In such a case, it can easily happen that an intermediate image is to the right of the next surface and hence is a virtual object for that surface. In the case of Figure 14 at the left, the power is positive, hence the convergent bundle of incident rays is made even more convergent which leads to a real image point. Indeed when so>0s_o>0 and P>0{\cal P}>0 then Eq. (13) implies that always si>0s_i>0. At the right of Figure 14 the power is negative but is not sufficiently strong to turn the convergent incident bundle into a divergent bundle. So the image is still real. However, the image will be virtual when the virtual object SS is to the right of FoF_o (which in this case is to the right of the surface) since then the bundle of rays converges so weakly that the surface turns it into a divergent bundle.

Two panels show converging incident rays from a virtual object S at spherical interfaces; the outgoing rays either diverge toward a virtual image or converge to a real image.

Figure 14:Imaging of a virtual object SS by a spherical interface with R>0R>0 between two media with refractive indices n1>n2n_1>n_2 (left) and n2>n1n_2>n_1 (right).

In conclusion: provided the sign convention listed in Table 1 is used, formula Eq. (13) can always be used to determine the image of a given object by a spherical surface.

The convention for sos_o, fof_o, sis_i, fif_i follows from the fact that these are zz-coordinates with the origin at vertex VV of the spherical surface (or the center of the thin lens) and the positive zz-axis is pointing to the right. The convention for the yy-coordinate follows from the fact that the yy-axis is positive upwards.

Table 1:Sign convention for spherical surfaces and thin lenses

quantitypositivenegative
sos_o, sis_i, fof_o, fif_icorresponding point is to the right of vertexcorresponding point is to the left of vertex
yoy_o, yiy_iobject, image point above optical axisobject, image point below optical axis
RRcenter of curvature right of vertexcenter of curvature left of vertex

5.3Stops

An element such as the rim of a lens or a diaphragm which determines the set of rays that can contribute to the image is called the aperture stop. An ordinary camera has a variable diaphragm.

The entrance pupil is the image of the aperture stop by all elements to the left of the aperture stop. In constructing the entrance pupil, rays are used which propagate from the right to the left. The image can be real or virtual. If there are no lenses between object and aperture stop, the aperture stop itself is the entrance pupil. Similarly, the exit pupil is the image of the aperture stop by all elements to the right of it. This image can be real or virtual. The entrance pupil determines for a given object the cone of rays in object space that contribute to the image, while the cone of rays leaving the exit pupil is the one taking part in image formation (see Figure 15).

For any object point, the chief ray is the ray in the cone that passes through the center of the entrance pupil, and hence also through the centers of the aperture stop and the exit pupil. A marginal ray is the ray that for an object point on the optical axis passes through the rim of the entrance pupil (and hence also through the rims of the aperture stop and the exit pupil).

The entrance pupil controls the cone of light accepted from an object point. For a camera focused on a distant scene, the nominal ff-number is the effective focal length ff divided by the entrance-pupil diameter DentranceD_{\mathrm{entrance}}:

f-number=fDentrance.\begin{align*} \text{f-number}=\frac{f}{D_{\mathrm{entrance}}}. \end{align*}

For example, f/2f/2 means f=2Dentrancef=2D_{\mathrm{entrance}}. At the same transmission and scene conditions, irradiance is approximately inversely proportional to the square of the ff-number, so f/1.4f/1.4 needs about half the exposure time of f/2f/2. Finite-distance imaging and transmission losses can modify this simple comparison.

Three lenses and a central aperture stop; dashed constructions locate the entrance pupil on the object side and exit pupil on the image side, with chief and marginal rays.

Figure 15:Aperture stop between the first and second lenses. The entrance pupil is the stop’s image seen from object space, and the exit pupil is its image seen from image space. The chief and marginal rays are shown.

6Beyond Gaussian Geometrical Optics

6.1Aberrations

For designing advanced optical systems Gaussian geometrical optics is not sufficient. Instead non-paraxial rays, and among them also non-meridional rays, must be traced using software based on Snell’s Law with the sine of the angles of incidence and refraction. Often many thousands of rays are traced to evaluate the quality of an image. It is then found that in general the non-paraxial rays do not intersect at the ideal Gaussian image point. Instead of a single spot, a spot diagram is found which is more or less confined. The deviation from an ideal point image is quantified in terms of aberrations. One distinguishes between monochromatic and chromatic aberrations. The latter are caused by the fact that the refractive index depends on wavelength. Recall that in paraxial geometrical optics Snell’s Law Eq. (11) is replaced by: niθi=ntθtn_i \theta_i = n_t \theta_t, i.e. sin⁡θi\sin \theta_i and sin⁡θt\sin \theta_t are replaced by the linear terms. If instead one retains the first two terms of the Taylor series of the sine, the errors in the image can be quantified by five monochromatic primary (Seidel) aberrations. The best known is spherical aberration, which is caused by the fact that for a convergent spherical lens, the rays that make a large angle with the optical axis are focused closer to the lens than the paraxial rays (see Figure 16).

Parallel rays entering a planoconvex lens at different heights cross the axis at different distances; marginal rays focus closer than paraxial rays.

Figure 16:Spherical aberration of a planar-convex lens.

Distortion is one of the five primary aberrations. It causes deformation of images due to the fact that the magnification depends on the distance of the object point to the optical axis.

For high-quality imaging, the aberrations have to be reduced by adding more lenses and optimizing the curvatures of the surfaces, the thicknesses of the lenses and the distances between them. For high-quality systems, a lens with an aspherical surface is sometimes used. Systems with very small aberrations are extremely expensive, in particular if the field of view is large, as is the case in lithographic imaging systems used in the manufacturing of integrated circuits as illustrated by the lithographic system in Figure 17.

Cutaway of an ASML NXE:3400B lithography machine; purple paths trace its internal mirror system.

Figure 17:ASML’s TWINSCAN NXE:3400B extreme-ultraviolet lithography system. The purple overlay traces its reflective projection optics; EUV systems use 13.5 nm light and mirrors rather than transmissive lenses (ASML product information).

6.2Diffraction

According to a generally accepted criterion formulated first by Rayleigh, aberrations start to deteriorate images considerably if they cause path length differences of more than a quarter of the wavelength. When the aberrations are less than this, the system is called diffraction limited.

Left plot shows the signed Airy field across the axis with side lobes; right image shows central bright intensity spot and faint concentric rings.

Figure 18:Left: cross section of the field of the Airy pattern. Right: intensity pattern of the Airy pattern.

Even if the wave transmitted by the exit pupil were perfectly spherical (no aberrations), its finite aperture causes diffraction. A point object therefore forms an Airy pattern rather than a point (Figure 18). For an ideal uniformly illuminated circular pupil, the central intensity spot has approximate full width at half maximum:

FWHM≈0.514 λ0NA,\begin{align*} \text{FWHM} \approx 0.514\,\frac{\lambda_0}{\mathrm{NA}}, \end{align*}

where λ0\lambda_0 is the vacuum wavelength and NA=nimagesin⁡θ\mathrm{NA}=n_{\mathrm{image}}\sin\theta is the image-space numerical aperture. Here θ\theta is the half-angle of the cone from the exit pupil to the image point; in air and the paraxial limit, NA≈a/L\mathrm{NA}\approx a/L for exit-pupil radius aa and distance LL from that pupil to the image. Diffraction depends on wavelength and therefore lies beyond pure geometrical optics. We treat aperture diffraction in Scalar Diffraction Optics.

7Chapter Summary

Footnotes
  1. See e.g. Born and Wolf, Principles of Optics, Chapter 1.

  2. For more details on conic sections and their properties in optics, see Jenkins and White, Fundamentals of Optics, Chapter 4.